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Why does Mozilla Support keep showing up under "Connected Services" at accounts.firefox.com?

  • 3 回覆
  • 0 有這個問題
  • 5 次檢視
  • 最近回覆由 Ken

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Just concerned what this is exactly because I noticed it once before and deleted it. Why does it need to be connected to my account? I tried Googling around to see if this was normal and I couldn't find anything.

Just concerned what this is exactly because I noticed it once before and deleted it. Why does it need to be connected to my account? I tried Googling around to see if this was normal and I couldn't find anything.
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Support.mozilla.org uses the Firefox Accounts to login on this site. https://support.mozilla.org/en-US/kb/firefox-accounts-supportmozillaorg https://support.mozilla.org/en-US/kb/access-mozilla-services-firefox-account

It used to be where the account for this site was only for this site.

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I think you might need to sign out on this site to terminate the connection. Hover over your user picture (K, I guess) to find the Sign Out button.

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James said

Support.mozilla.org uses the Firefox Accounts to login on this site. https://support.mozilla.org/en-US/kb/firefox-accounts-supportmozillaorg https://support.mozilla.org/en-US/kb/access-mozilla-services-firefox-account It used to be where the account for this site was only for this site.

Is it normal for Mozilla Support to be logged into my account when I wasn't even using it? This is the second time I've found it logged into my Firefox account and I'm just trying to make sure my account is secure and that this is normal behavior. In fact, this is the first time I've logged into support.mozilla.org. How could that be? Any ideas?

In fact, I've already signed out of the service just now and I'm still able to make this post. What gives?

jscher2000 - Support Volunteer said

I think you might need to sign out on this site to terminate the connection. Hover over your user picture (K, I guess) to find the Sign Out button.

Yes, thank you, I'm actually trying to determine what this activity is about. I wasn't really clear about this.

由 Ken 於 修改